By: Dorris Emailed: 1785 times Printed: 2623 times
case $variable-name in pattern1) command ... .. command;; pattern2) command ... .. command;; patternN) command ... .. command;; *) command ... .. command;; esac
The $variable-name is compared against the patterns until a match is found. The shell then executes all the statements up to the two semicolons that are next to each other. The default is *) and its executed if no match is found. For e.g. write script as follows:
$ cat > car
# if no vehicle name is given
# i.e. -z $1 is defined and it is NULL
# if no command line arg
if [ -z $1 ]
rental="*** Unknown vehicle ***"
elif [ -n $1 ]
# otherwise make first arg as rental
case $rental in
"car") echo "For $rental Rs.20 per k/m";;
"van") echo "For $rental Rs.10 per k/m";;
"jeep") echo "For $rental Rs.5 per k/m";;
"bicycle") echo "For $rental 20 paisa per k/m";;
*) echo "Sorry, I can not gat a $rental for you";;
Save it by pressing CTRL+D and
run it as follows:
$ chmod +x car
$ car van
$ car car
$ car Maruti-800
First script will check, that if $1(first command line argument) is given or
not, if NOT given set value of rental variable to "*** Unknown vehicle
***",if command line arg is supplied/given set value of rental variable to
given value (command line arg). The $rental is compared against the patterns
until a match is found.
For first test run its match with van and it will show output "For van Rs.10 per k/m."
For second test run it print, "For car Rs.20 per k/m".
And for last run, there is no match for Maruti-800, hence default i.e. *) is executed and it prints, "Sorry, I can not gat a Maruti-800 for you".
Note that esac is always required to indicate end of case statement.
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