Type Conversions in C (String to Integer, isdigit() etc)
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A char is just a small integer, so chars may be freely used in arithmetic expressions. This permits considerable flexibility in certain kinds of character transformations. One is exemplified by this naive implementation of the function atoi, which converts a string of digits into its numeric equivalent.
/* atoi: convert s to integer */ int atoi(char s[]) { int i, n; n = 0; for (i = 0; s[i] >= '0' && s[i] <= '9'; ++i) n = 10 * n + (s[i]  '0'); return n; }the expression
s[i]  '0'gives the numeric value of the character stored in s[i], because the values of '0', '1', etc., form a contiguous increasing sequence.
Another example of char to int conversion is the function lower, which maps a single character to lower case for the ASCII character set. If the character is not an upper case letter, lower returns it unchanged.
/* lower: convert c to lower case; ASCII only */ int lower(int c) { if (c >= 'A' && c <= 'Z') return c + 'a'  'A'; else return c; }This works for ASCII because corresponding upper case and lower case letters are a fixed distance apart as numeric values and each alphabet is contiguous  there is nothing but letters between A and Z. This latter observation is not true of the EBCDIC character set, however, so this code would convert more than just letters in EBCDIC.
The standard header <ctype.h>, defines a family of functions that provide tests and conversions that are independent of character set. For example, the function tolower is a portable replacement for the function lower shown above. Similarly, the test
c >= '0' && c <= '9'can be replaced by
isdigit(c)We will use the <ctype.h> functions from now on.
There is one subtle point about the conversion of characters to integers. The language does not specify whether variables of type char are signed or unsigned quantities. When a char is converted to an int, can it ever produce a negative integer? The answer varies from machine to machine, reflecting differences in architecture. On some machines a char whose leftmost bit is 1 will be converted to a negative integer (``sign extension''). On others, a char is promoted to an int by adding zeros at the left end, and thus is always positive.
The definition of C guarantees that any character in the machine's standard printing character set will never be negative, so these characters will always be positive quantities in expressions. But arbitrary bit patterns stored in character variables may appear to be negative on some machines, yet positive on others. For portability, specify signed or unsigned if noncharacter data is to be stored in char variables.
Relational expressions like i > j and logical expressions connected by && and  are defined to have value 1 if true, and 0 if false. Thus the assignment
d = c >= '0' && c <= '9'sets d to 1 if c is a digit, and 0 if not. However, functions like isdigit may return any nonzero value for true. In the test part of if, while, for, etc., ``true'' just means ``nonzero'', so this makes no difference.
Implicit arithmetic conversions work much as expected. In general, if an operator like + or * that takes two operands (a binary operator) has operands of different types, the ``lower'' type is promoted to the ``higher'' type before the operation proceeds. The result is of the integer type. If there are no unsigned operands, however, the following informal set of rules will suffice:
 If either operand is long double, convert the other to long double.
 Otherwise, if either operand is double, convert the other to double.
 Otherwise, if either operand is float, convert the other to float.
 Otherwise, convert char and short to int.
 Then, if either operand is long, convert the other to long.
Conversion rules are more complicated when unsigned operands are involved. The problem is that comparisons between signed and unsigned values are machinedependent, because they depend on the sizes of the various integer types. For example, suppose that int is 16 bits and long is 32 bits. Then 1L < 1U, because 1U, which is an unsigned int, is promoted to a signed long. But 1L > 1UL because 1L is promoted to unsigned long and thus appears to be a large positive number.
Conversions take place across assignments; the value of the right side is converted to the type of the left, which is the type of the result.
A character is converted to an integer, either by sign extension or not, as described above.
Longer integers are converted to shorter ones or to chars by dropping the excess highorder bits. Thus in
int i; char c; i = c; c = i;the value of c is unchanged. This is true whether or not sign extension is involved. Reversing the order of assignments might lose information, however.
If x is float and i is int, then x = i and i = x both cause conversions; float to int causes truncation of any fractional part. When a double is converted to float, whether the value is rounded or truncated is implementation dependent.
Since an argument of a function call is an expression, type conversion also takes place when arguments are passed to functions. In the absence of a function prototype, char and short become int, and float becomes double. This is why we have declared function arguments to be int and double even when the function is called with char and float.
Finally, explicit type conversions can be forced (``coerced'') in any expression, with a unary operator called a cast. In the construction
(type name) expression
the expression is converted to the named type by the conversion rules above. The precise meaning of a cast is as if the expression were assigned to a variable of the specified type, which is then used in place of the whole construction. For example, the library routine sqrt expects a double argument, and will produce nonsense if inadvertently handled something else. (sqrt is declared in <math.h>.) So if n is an integer, we can use
sqrt((double) n)to convert the value of n to double before passing it to sqrt. Note that the cast produces the value of n in the proper type; n itself is not altered. The cast operator has the same high precedence as other unary operators, as summarized in the table at the end of this chapter.
If arguments are declared by a function prototype, as the normally should be, the declaration causes automatic coercion of any arguments when the function is called. Thus, given a function prototype for sqrt:
double sqrt(double)the call
root2 = sqrt(2)coerces the integer 2 into the double value 2.0 without any need for a cast.
The standard library includes a portable implementation of a pseudorandom number generator and a function for initializing the seed; the former illustrates a cast:
unsigned long int next = 1; /* rand: return pseudorandom integer on 0..32767 */ int rand(void) { next = next * 1103515245 + 12345; return (unsigned int)(next/65536) % 32768; } /* srand: set seed for rand() */ void srand(unsigned int seed) { next = seed; }
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Comments(2)
1.  View Commentgood for us View Tutorial By: soumen chakraborty at 20080825 01:28:30 
2.  View Commentcan u be more specific like put up some more heading so that it looks good.i am getting bored reading this and cant able too understand anything i have to submit and assigntment on type conversion in c tommmorrow please write another article for me plzz View Tutorial By: Jass at 20121029 03:51:29 
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