# Calculator in C

By: Emiley J Emailed: 1768 times Printed: 2515 times

 By: rohit kumar - how this program is work By: Kirti - Hi..thx for the hadoop in By: Spijker - I have altered the code a By: ali mohammed - why we use the java in ne By: ali mohammed - why we use the java in ne By: mizhelle - when I exported the data By: raul - no output as well, i'm ge By: Rajesh - thanx very much... By: Suindu De - Suppose we are executing

This is a simple calculator written in C. To use this calculator, just type the number, followed by the operand and then by another number. The application will then display the result. After the result is displayed, the program goes into the loop which asks if they want to do another calculation. If y is pressed, another calculation can be carried out.

``` #include int main() { double number1 = 1.0; double number2 = 2.0; char operation = '+'; char answer = 0; switch(operation) { case '+': printf("= %lf\n", number1 + number2); break; case '-': printf("= %lf\n", number1 - number2); break; case '*': printf("= %lf\n", number1 * number2); break; case '/': if(number2 == 0) printf("\n\n\aDivision by zero error!\n"); else printf("= %lf\n", number1 / number2); break; case '%': if((long)number2 == 0) printf("\n\n\aDivision by zero error!\n"); else printf("= %ld\n", (long)number1 % (long)number2); break; default: printf("\n\n\aIllegal operation!\n"); } } ```

 1 View Comment`The program doesn't work as how it is described.` View Tutorial          By: Gurucharan at 2011-02-03 09:21:18 2 View Comment`Its not working ave made a few adjustments to it though and it okay now` View Tutorial          By: amg at 2011-11-04 13:48:09 3 View Comment```the 2 not required lines 1) #include 2) char answer = 0 Add a line will necessary to :- return 0;``` View Tutorial          By: saurabh at 2012-02-20 06:33:57

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