## Question

A wave has a speed of 330 metre/second and frequency 500 hertz. The phase difference between two adjacent points is π/3 radian. What will be the path difference between them?

### Solution

Phase difference = & path difference = 11 cm.

Velocity of the wave, *v* = 330 m/s, frequency, *n* = 500 Hz. According to the formula *v* = nλ, the wavelength is

If âˆ†*x* be the minimum distance two points, then the phase difference between them is

Here . Therefore, the path difference

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