# Programming Tutorials

## Find the biggest number in Shell Script

By: Vivek G in Linux Tutorials on 2011-01-29

This shell script shows how to find the biggest number from three given numbers. The algorithm is as follows:
```#      1) START: Take three nos as n1,n2,n3.
#      2) Is n1 is greater than n2 and n3, if yes
#         print n1 is bigest no goto step 5, otherwise goto next step
#      3) Is n2 is greater than n1 and n3, if yes
#         print n2 is bigest no goto step 5, otherwise goto next step
#      4) Is n3 is greater than n1 and n2, if yes
#         print n3 is bigest no goto step 5, otherwise goto next step
#      5) END
```
```    if [ \$# -ne 3 ]
then
echo "\$0: number1 number2 number3 are not given" >&2
exit 1
fi
n1=\$1
n2=\$2
n3=\$3
if [ \$n1 -gt \$n2 ] && [ \$n1 -gt \$n3 ]
then
echo "\$n1 is Bigest number"
elif [ \$n2 -gt \$n1 ] && [ \$n2 -gt \$n3 ]
then
echo "\$n2 is Bigest number"
elif [ \$n3 -gt \$n1 ] && [ \$n3 -gt \$n2 ]
then
echo "\$n3 is Bigest number"
elif [ \$1 -eq \$2 ] && [ \$1 -eq \$3 ] && [ \$2 -eq \$3 ]
then
echo "All the three numbers are equal"
else
echo "I can not figure out which number is biger"
fi
```